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initial angular speed of 18.0rad/s and rolls in a straight line without slipping. If the rotation slows with an angular accelation of magnitude 1.90rad/s^2, how far does the coin roll before coming to rest?

2007-11-26 16:19:30 · 1 answers · asked by mary s 1 in Science & Mathematics Physics

1 answers

w=18-1.9*t
when w=0, the coin stops rolling
t=18/1.9
The number of radians is
th=18*t-.5*1.9*t^2

th=85.26 radians

there are 2* pi radians in the circumference of the coin
so
85.26*3.14*2.4 is the distance rolled
642.5 cm

j

2007-11-27 04:50:24 · answer #1 · answered by odu83 7 · 0 1

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