Given the initial velocity and degree of a kicked football, how do you find its hangtime, max height, range?

Answer 1

You would start by finding the horizontal and vertical components (horizontal and vertical) of the vector giving by the velocity and degree.

horizontal velocity = vcosA
vertical velocity = vsinA

Then you find how long it will stay in the air by using this formula:

x=vt-1/2at^2 ------- In this case we want to use the vertical velocity and gravity's acceleration (x = 0 because we want to know at what time it will hit the ground again)

0=vtsinA-4.9t^2
t= vsinA/4.9 ---------- This gives us the time it is it in the air

It's max height will be half of the time it is in the air.

Finally, it's distance will be it's horizontal velocity times how long it was in the air:

d=vcosAvsinA/4.9

Answer 2

First you need to discover how long it is going to take for the ball to drop 6.2m (Dist. = a million/2g x t^2) will become 6.2m = 5t^2, t^2 = 6.2/5. t^2 = a million.24seconds ^2, t = a million.a million seconds. So, now: We enable gravity handle getting the ball down. OUR pastime is to get the ball to commute 10.4m in a million.a million seconds. 10.4m/a million.1s = 9.40 5 m/s. Richard