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what would be the answer for this problem?

3x-5y= 13
x-2y=5

my answer: 2x-3y=8

2007-11-26 15:56:26 · 3 answers · asked by ALESANA 7 in Education & Reference Homework Help

3 answers

Nope, sorry.
You're actually trying to solve for x and y.
The first step is to multiply one of the equations by a constant so that EITHER the x-terms OR the y-terms have the same coefficient. In this case, it'd be easier to change the x-term in the second equation to 3x.
3(x - 2y) = 3(5)
3x-6y = 15
NOW you should subtract one equation from the other, so you have:
3x - 6y = 15
-[3x - 5y = 13]
-1y = 2
And you can solve to get y = -2.
Then you just have to plug it in to either of the original equations to get x:
x - 2(-2) = 5
x + 4 = 5
x = 1
So the answer, in short, is:
x = 1, y = -2.

2007-11-26 16:04:39 · answer #1 · answered by niki 2 · 0 0

I think what you're supposed to do is this:

You got 2 equations:

3x - 5y = 13 & x - 2y = 5

So, take the last one multiply both sides by 3 and subtract it from the top one to get a single variable = to a number.

3x - 5y = 13
3x - 6y = 15

gives y = -2

Then, plug this back into one of the original equations to get x

x - 2(-2) = 5 : x = 1

So x = 1, y = -2

2007-11-26 16:07:16 · answer #2 · answered by Flying Dragon 7 · 0 0

That's wrong. You have to find x and y.

First, multiply second equation by 3
3x-5y = 13
3x - 6y = 15

Subtract 2 from 1 to find y

y = -2

Then you plug y into the equations to find x = 1

So your answer is (1,-2)

2007-11-26 16:00:55 · answer #3 · answered by Luna 4 · 0 0

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