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5x-10>2x+4
5x-10+10>2x+4+10 [adding 10 to both sides]
5x>2x+14
5x-2x>2x+14-2x
3x>14[subtracting 2x from both sides]
x>14/3 [dividing both sides by 3]
x>4 2/3
2007-11-26 15:34:11
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answer #1
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answered by alpha 7
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5x-10>2x+4
-2x -2x
3x-10>4
+10 +10
3x>14
divided by 3
x>4 2/3
2007-11-26 15:32:03
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answer #2
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answered by cuteiswhatweallaimfor 3
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12
2007-11-26 15:33:02
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answer #3
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answered by Anonymous
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x>14/3 or 4 2/3
2007-11-26 15:31:14
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answer #4
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answered by Chelsi 2
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5x-10>2x+4
3x > 14
x> 14/3
2007-11-26 15:33:27
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answer #5
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answered by m!l@ 2
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5x-10>2x+4
5x-10<-2x-4
treat the equalities like an equal sign and solve for x
2007-11-26 15:31:28
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answer #6
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answered by dreamingofthosebabyblues 3
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I won't solve it for you, but I will tell you how it is done. Just pretend the > is an = sign. Can you solve it then? I mean, keep it as > but solve as if it said =. In this problem it makes no difference. You would only change it if you were multiplying or dividing by a negative, in which case you flip the inequality.
2007-11-26 15:34:29
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answer #7
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answered by daddyslildefect0613 1
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5x-10>2x+4
5x-2x>4+10
3x> 14
x>14/3
2007-11-26 15:30:44
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answer #8
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answered by john b2 1
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5x-10>2x+4
5x-2x>4+10
3x>14
x>14/3
2007-11-26 15:32:40
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answer #9
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answered by FigureSk8ingAddict 3
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3x>14 and then x>14/3. Simple.
2007-11-30 15:28:36
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answer #10
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answered by t 2
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