after how many hrs will the faster car be 42miles ahead of the slower once?
2007-11-26 15:03:58 · 7 answers · asked by kpd123 1 in Science & Mathematics ➔ Mathematics
Relative speed = 7 mph
t = 42 / 7 h
t = 6 h
2007-11-26 21:07:13 · answer #1 · answered by Como 7 · 0⤊ 1⤋
Each hour, the faster car travels seven miles further than the slower car. So, the answer to the problem can be found simply by dividing 42 by 7, = 6 hours.
2007-11-26 15:07:01 · answer #2 · answered by RavenSierra 3 · 2⤊ 0⤋
Let F represent the fast car's milage.
Let S represent the slower car's milage.
Let t represent the time in hours.
F=52t
S=45t
F-S=42 <
7t=42
t=6hrs
In 6 hours time, the fast car sill be 42 miles ahead.
2007-11-26 15:12:13 · answer #3 · answered by SaintPretz59 4 · 1⤊ 0⤋
x = time in hours
Finding the time:
x(52 - 45) = 42
7x = 42
x = 6
Answer: After 6 hours the faster car would be ahead by 42 miles.
Proof (distances covered and distance difference after 6 hours):
(52 mph * 6 hr) - (45 mph * 6 hr) = 42 mi
312 mi - 270 mi = 42 mi
42 mi = 42 mi
2007-11-26 15:14:46 · answer #4 · answered by Jun Agruda 7 · 3⤊ 0⤋
a million) they're going to fulfill after 5 hours. After a million hour Mark is 20m from the initiating factor and Michelle is 0m After 2 hours Mark is 40m and Michelle is 25 After 3 hours Mark is 60 and Michelle is 50 After 4 hours Mark is 80 and Michelle is 75 After 5 hours Mark is one hundred and Michelle is one hundred 2)He changed into 30 miles from his domicile even as he had to reveal round. it can take him 3 hours to holiday 30 miles in a % of 10mph. it can take him yet another a million hour to flow decrease back to his domicile in 30mph. 3)enable the speed of the first vehicle be x enable the speed of the 2d vehicle be x+9 subsequently in a million hour the vehicles will holiday x miles and (x+9) miles respectively for this reason, x+ (x+9) = one hundred seventy 5 x +x +9 =one hundred seventy 5 2x = one hundred seventy 5-9 2x=166 x=166/2=80 3 for this reason the speed of the first vehicle is 80 3 mph and the speed of the 2d vehicle is 80 3+9 =92mph 4)enable the speed of the first vehicle be x Then the speed of the 2d vehicle is 3x-8 the gap travelled by the vehicles in 10 hours will be 10x and 10(3x-8) respectively. subsequently, 10(3x-8)-10x=240 30x-80-10x=240 30x-10x=240+80 20x=320 x=320/20=16 for this reason the speed of the first vehicle is 16mph and the speed of the 2d vehicle is 40mph. desire this answer helped you.
2016-10-25 02:57:04 · answer #5 · answered by ? 4 · 0⤊ 0⤋
42 = 52t - 45t
42 = 7t
t = 42/7 = 6hrs
2007-11-26 15:07:10 · answer #6 · answered by john b2 1 · 1⤊ 0⤋
I concur with all three answers!!!
2007-11-26 15:13:16 · answer #7 · answered by huntnikk2000 3 · 0⤊ 0⤋