7<1-x<13
i'm confusing on this .
2007-11-26 14:28:47 · 7 answers · asked by nirvan5a 2 in Science & Mathematics ➔ Mathematics
you have to get x alone in the middle.
but lets say that you subtract 1 from the middle...you have to subtract 1 from both the left and the right side.
2007-11-26 14:31:37 · answer #1 · answered by gilligann :) 2 · 3⤊ 1⤋
7< 1-x < 13
so subtract 1 through from inequality
6 < -x < 12
now negate the inequality to make x sign positive
so -6 > x > -12 ( as u negate , inequality signs also changed up)
so -12 < x < -6 is answer
2007-11-26 22:40:15 · answer #2 · answered by sapna 1 · 0⤊ 2⤋
7 < 1-x < 13
7+x < 1 < 13+x
6+x < 0 < 12+x
6 < x < 12
Does that help?
2007-11-26 22:32:39 · answer #3 · answered by beyondearthfiles 2 · 1⤊ 1⤋
1 - x < 13
- x < 12
x > - 12
7 < 1 - x
6 < - x
x < - 6
- 12 < x < - 6
2007-11-27 13:43:50 · answer #4 · answered by Como 7 · 2⤊ 1⤋
7 <1-x< 13
- 1 -1 -1
------ -------- -----
6 < -x < 12
then divide by the negative
-6 < x < -12
2007-11-26 22:35:42 · answer #5 · answered by j wiggs 2 · 1⤊ 1⤋
sbtract with 1
6<-x<12
devide with -1(for making x positive)
-6>x>-12
simply its mean the value of x belongs to (-6,-12)
2007-11-26 22:41:35 · answer #6 · answered by ♫●GARV●♫ 6 · 1⤊ 2⤋
-6>x>-12
subtract one from every number to cancel in the middle and theyn devide all by -1 so make x positive.
2007-11-26 22:31:50 · answer #7 · answered by creede_horse_lover 2 · 1⤊ 1⤋