Fully Factorise: xy^2 - x^2y?

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Fully Factorise: xy^2 - x^2y?

Thanks!

2007-11-26 13:54:20 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

3 answers

(xy) (y - x)

2007-11-26 21:29:39 · answer #1 · answered by Como 7 · 3⤊ 1⤋

The above equates to 2q(p-q) which would be in spite of if p and q are integers to initiate with. you may do (p-q) first, then multiply this via q. Then it is not appropriate in spite of if q(p-q) is extraordinary or perhaps because of the fact any integer expanded via 2 is even. in case you have been thinking what might ensue if p=q or p and q are 0, 0 is an integer and it truly is even. Fretty, you have further q^2 on extremely of taking it away.

2016-12-30 05:00:33 · answer #2 · answered by jun 3 · 0⤊ 0⤋

xy(y-x)

2007-11-26 13:56:43 · answer #3 · answered by aaron.brake 3 · 2⤊ 2⤋