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What volume (mL) of 0.420 M potassium hydroxide solution would just neutralize 49.0 ml of 0.291 M H2SO4 solution?

2007-11-26 13:28:20 · 1 answers · asked by starrynight4592 1 in Science & Mathematics ➔ Chemistry

1 answers

2KOH + H2SO4 ===> K2SO4 + 2H2O

Let the KOH solution be called KS. Let the H2SO4 solution be called HS.

49.0mLHS x 0.291molH2SO4/1000mLHS x 2molKOH/1molH2SO4 x 1000mLKS/0.420molKOH = 67.9 mL KOH solution

2007-11-26 13:53:38 · answer #1 · answered by steve_geo1 7 · 0⤊ 0⤋