Steel sliding across steel has a of .41. 50 N of steel is pushed with a force of 22 N. What would happen to the piece of steel – stay still, move at a constant velocity, or accelerate?
2007-11-26 12:49:36 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Physics
If that box is actually coefficient of static friction, then the box accelerates.
Ffric max = mu(static)x Fnormal = 0.41x50 = 20.5 N
Therefore, friction consumes 20.5 N of force before it starts sliding, but you still have 1.5 N left in your force, so there is a positive net force, therefore the box accelerates.
2007-11-26 12:56:15 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Your graphic didn't work so I assume that .41 is the coefficient of static friction.
The force required to get the steel moving is uN = umg. Plug in the coefficient, the mass, and the local acceleration of gravity. If this value is less than 22 N, the steel will move. If not, it won't budge. You can't say whether or not it will move at a constant velocity because the coefficients of static and kinetic friction are almost always different.
2007-11-26 20:54:33 · answer #2 · answered by jgoulden 7 · 0⤊ 0⤋