help with logarithems. 16 ln X = 30?

Answer 1

Hi,

For this equation, you need to isolate for x alone by first dividing both sides of the equation by 16 to get the following:

ln (x) = 30 / 16

Now, in order to get the x alone, we need to raise both sides of the equation by base e to undo the natural log expression and therefore get:

e ^ ln(x) = e^ (30/16)

x = e^(30/16) <== most exact answer

or...

x = 6.521 <==== decimal equivalent

I hope that helps you out! Please let me know if you have any other questions!

Sincerely,

Andrew

Answer 2

Jeez, this is algebra not logarithms.

divide by 16, take the natural anti log of both sides.

X = e^(30/16)

Remember. A logarithm is an exponant. We usually use 10 as the base, so LOG 100 = 2 because 10^2 =100

The base for the natural log is 'e' or 2.7183...

so ln 100 = 4.6052 because e^4.6052 = 100

Answer 3

16 ln X = 30
ln X = 30/16
X = e^(30/16)

Answer 4

lnx = 30/16

x = Anti ln (30/16)

= e^(30/16)
6.52081912033011

Answer 5

16 ln(x) = 30

divide by 16

ln(x) = 30/16 = 15/8

x = e^(15/8) = 6.521

Answer 6

ln X = 30/16

ln is log to the base e.

e^ (30/16) = X.

You can evaluate that exponent on a calculator if decimal accuracy is required for the answer.

Answer 7

Rearrange:
ln x = 30/16

Antilog:
x = e^(15/8)= 6.52081912

Answer 8

Ha, you must be in Math 111 preparing for your final. Oh, how I know the feeling. Remember that ln is natural log or loge, so rewrite it as 16loge^30=X, your calculator should be able to take it from there.

Answer 9

ok, so my suggestion is to say first divide both sides by 16.

1) ln X = 30/16

then we can say that any time you see a natural log (ln) that you can get rid of it by raising both sides by an exponent of e.

2) X= (30/16)^e

and that is it.

Answer 10

ln x = 30/16

e^{ln x} = e^{15/8}

x = e^{15/8}