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Janet jumps off a high-diving platform with a horizontal velocity of 2.8 m/s and lands in the water 2.6 s later.

How high is the platform and how far from the base of the platform does she land?

2007-11-26 11:05:46 · 1 answers · asked by bebostep 2 in Science & Mathematics Physics

1 answers

y(t)=-.5*9.8*t^2
y(2.6)=.5*9.8*2.6^2
the platform is 33 m above the water

x(t)=2.8*t
x(2.6)=2.8*2.6
she lands 7.3 m from the base of the platform

j

2007-11-28 05:14:21 · answer #1 · answered by odu83 7 · 0 0

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