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I found this riddle at a high IQ society I belong to and have yet to see anyone break it - I figured it out, can you? Do you think you're smart enough to break the code? It's actually quite simple, so I'm hoping a population with limited knowledge of ciphers will be able to break this quickly.


Can you find the hidden message? The two words are represented below by the numbers where each number represents a letter...here's a clue: My first and last are in CUBES.

21 4 19 27 10 / 14 25 18 40 42

First person to provide me the correct response AND the logic behind the cipher will win 10 points.

Come on Yahoo Answers, show me what you got.

2007-11-26 10:39:05 · 3 answers · asked by CubeScience 3 in Science & Mathematics Mathematics

Clue #2 - the first and last letter is S.

Apparently everyone is having a pretty hard time with this.

2007-11-28 12:32:48 · update #1

3 answers

21 4 19 27 10 / 14 25 18 40 42

I think I figured it out, but I found a mistake in your sequence...
Since you provided the clue that 21 = S and 42 = S I immediately thought that each number represented a position in the alphabet with a sequence. I tried dozens of sequences but then I noticed your clue that it didn't require indepth knowledge so I stuck to well known sequences including Primes!!..

Primes is the Prime! LOL

When you deduct the Prime sequence from you code you're left with the original letter number

S is the 19th letter in the alphabet, 2 is the first prime number, 2 + 19 = 21, 3 is the second number in the prime sequence, so 3 - 4 = 1, so 4 = A, the next is 19 - 5 = 14 which is N...so on and so forth...the sequence followed this code nicely until I go to 10...but it picks up again after that, so I figured it was an oversight (Am i right???)

the code spells SANTA CLAUS

2007-11-29 08:34:02 · answer #1 · answered by Caramilk 1 · 2 0

I've been working on this too for several days. I'm thinking that cubes (e.g. x^3) must be involved. Also I wonder if SUGAR / CUBES might be the answer...

Any more hints?

Drat! Cubes was a big red herring... I've been off on the wrong tangent for days because of that. How smart is that?!? :-)

I agree with the SANTA CLAUS answer below, but am also puzzled by the odd '9' that is in there... what's up with that?

S = 19 --> + 2 = 21
A = 1 --> + 3 = 4
N = 14 --> + 5 = 19
T = 20 --> + 7 = 27
A = 1 --> + 9 = 10 <--- ???
C = 3 --> + 11 = 14
L = 12 --> + 13 = 25
A = 1 --> + 17 = 18
U = 21 --> + 19 = 40
S = 19 --> + 23 = 42

2007-11-29 15:51:55 · answer #2 · answered by Puzzling 7 · 0 0

dang this is hard

2007-11-27 22:47:10 · answer #3 · answered by Anonymous · 0 0

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