for the first one you did almost all of it correct, but 0/19 is 0
so your x should equal 0
for the second one the x's cancel out so htere is no solution for this problem
2007-11-26 10:17:59
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answer #1
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answered by Ms. Exxclusive 5
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you have 2 trick problems
for the first one,
19x=0
you have to divide both sides by 19. and zero divided by anything is zero, so the answer is x=0
and just btw, what you did was to divide 19 by zero. that answer would come out to be undefined, not 19. you cant divide by 0 and get a real number. answer is always undefined.
for the second one, the x's would cancel out (an 8 minus 8), so there is no solution
you can't just add the 8's
hope that helped
2007-11-26 18:23:23
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answer #2
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answered by abstractcollaterals 2
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7x + 30 = -12x + 30
19x + 30 = 30
l
V
19x =0
---- ----
19 19
----------------
x=0
your should dived 0 by 19 (not 19 by 0) and so you get X=0 which is a vertical line if your graphing
8x - 3 = 8x + 13
l
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8x = 8x + 16
-8x -8x
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x=16
you subtract not add 8.
2007-11-26 21:38:46
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answer #3
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answered by joey97501 3
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for the first one the answer is 0 because 19 divided by 0 equals 0 (really because anything multiplied or divided by 0 equals 0)
for the second one, you just have to finish the problem-
16x=0
just divide 16 by 0 and get 0 as the answer just like before
2007-11-26 18:20:09
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answer #4
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answered by justme 3
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On the 1st one, you did everything right except the last step. When you divide 19 by 0, the answer is 0, not 19.
You cant answer the next one. There is no answer to it. (No Solution)
2007-11-26 18:20:12
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answer #5
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answered by :) 4
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Anything multiplied or divided by 0 = 0
2007-11-26 18:23:57
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answer #6
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answered by momo5j7 5
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What Ms. Exxclusive said
2007-11-26 18:20:55
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answer #7
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answered by dogsafire 7
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They are both false statements.
You were pretty much doing the right thing,
But the answer for each would be
"False Statement"
2007-11-26 18:19:08
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answer #8
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answered by Anonymous 3
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*you cant divide by 0
2007-11-26 18:19:15
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answer #9
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answered by Questions? 2
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hmjhgj
2007-11-26 18:17:30
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answer #10
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answered by Anonymous
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