10 points who can explain this or make it as easy as possible for me?

Question

1: Steven has 3 pounds of brand 121 nuts that sell for $2.23 a pound. He also has brand 330 nuts that sell for $1.75 a pound. If he wants a mixture of nuts that sell for $1.93 a pound, how many pounds of brand 330 should he add?






3 pounds
5 pounds
6 pounds
8 pounds


2: Brianna has 2 pounds of brand 176 nuts that sell for $3 a pound. She also has brand 391 nuts that sell for $1.74 a pound. If she wants a mixture of nuts that sell for $2.58 a pound, how many pounds of brand 391 should she add?






2 pounds
1/2 pound
1 pound
3 pounds


3: Mr. Lowe bought some three-cent stamps and some two-cent stamps. The total cost was $8.90. How many stamps of each kind did he buy if the total number was 345 stamps?






200 three-cent and 145 two-cent
175 three-cent and 170 two-cent
145 three-cent and 200 two-cent
150 three-cent and 195 two-cent


4: A bank teller has a package of five-dollar bills and a package of ten-dollar bills. The total value is $1110. How many bills of each denomination has he, if the total number of bills is 142?






80 fives and 62 tens
63 tens and 79 fives
42 tens and 100 fives
80 tens and 62 fives


5: How many pounds of coffee selling for $2.25 a pound should be added to eight pounds of coffee selling for $3.75 a pound to create a blend, which will sell for $3.45 a pound?






1 pound
2 pounds
3 pounds
4 pounds

Answer 1

I'm not trying to be rude, but unless someone has an hour's free time, no one is going to thoroughly explain each of these problems to you.

If I were you, I would post each problem as an individual question on Yahoo! Answers. You will receive more answers, and people will feel like they have the time to explain the problem.

Answer 2

x lbs of 330 nuts.
3*2.23 +x*1.75 = (3+x)*1.93
6.69 + 1.75x = 5.79 + 1.93x
.18x = .90
x = 5

the others can all be done the same way except 4.

say there are x $5 bills and y $10s
x+y = 142
5x+10y = 1110
divide eq 2 by 5
x+2y = 220
subtract eq 1
y = 78
plug in eq 1
x = 64
check 5x+10y = 320 + 780 = 1110

Answer 3

x=pounds of 330 to be added
Equation is :
3*2.23 +1.75x = (x+3)1.93

Solve 2nd problem same way as first one

x = 3 cent stamps
345-x = 2 cent stamps
3x +2(345-x) = 890

Lats problem is just like third problem

Answer 4

These are mixture problems. Lets do the first one

3lbs(2.23/lb) + xlbs(1.75/lb) = (3+x)lbs(1.93/lb)
6.69 + 1.75X = 5.79 + 1.93X
90=22X
4.09 = X
The others follow the same pattern