balancing chemical equations?

Question

I was learning these and i went to do them and i forgot could you show like the steps in how you do them?

1.aluminum sulfate +barium chloride --> aluminum chloride + barium sulfate

2.sodium hydrogen carbonate --> sodium carbonate + carbon dioxide +water

Answer 1

first u have to write them in terms of symbols:

1. Al2(SO4)3 + BaCl2 --> AlCl3 + BaSO4

now we need 2 Als on the right

Al2(SO4)3 + BaCl2 --> 2AlCl3 + BaSO4

now we see that we need 6 Cl on the left so we add a 3 in front of BaCl2

Al2(SO4)3 + 3BaCl2 --> 2AlCl3 + BaSO4

now we need 3 Ba on the right

Al2(SO4)3 + 3BaCl2 --> 2AlCl3 + 3BaSO4 all done!

2. 2NaHCO3 --> Na2CO3 + CO2 + H2O

Answer 2

1.aluminum sulfate +barium chloride --> aluminum chloride + barium sulfate

Al2(SO4)3(aq) + 3 BaCl2(aq) -------> 2AlCl3(aq) + 3 BaSO4(s)

2.sodium hydrogen carbonate --> sodium carbonate + carbon dioxide + water

2 NaHCO3(s) ------heat------> Na2CO3(s) + CO2(g) + H2O(g)

There is no particular "trick" to balancing these. The main thing is to make SURE that you have the correct formulas. It is called "balancing by inspection." You just count atoms on each side of the equation and adjust the coefficients until you have the same number of each type of atom on each side of the equation. But once you have written the correct formulas, do NOT change the formulas to help balancing.

Answer 3

1. Al2(SO4)3 + BaCl2 ===> AlCl3 + BaSO4

Because BaSO4 is 1:1, try 3 in front of that:

Al2(SO4)3 + 3BaCl2 ===> AlCl3 + 3BaSO4

That leads to the balanced equation:

Al2(SO4)3 + 3BaCl2 ===> 2AlCl3 + 3BaSO4

2. NaHCO3 ===> Na2CO3 + CO2 + H2O

Two Na's on the right, one on the left, so:

2NaHCO3 ===> Na2CO3 + CO2 + H2O

Answer 4

H2 + Br2 = HBr & HBr You have to make sure that there is the same amount of elements on each side of the equation. so for this equation it makes 2 molecules of HBr because ther are 2 of each element on the other side of the equation.