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2007-11-26 08:39:35 · 3 answers · asked by cerelac 2 in Science & Mathematics Physics

where is the answer :o

2007-11-26 08:47:29 · update #1

3 answers

Assuming that the pool is full of water with density 1000 kg / m^3, the pressure is

P(atmospheric) + p g h

where P is the atmospheric pressure at the surface
p the density of water
g the local acceleration of gravity
h the depth (in this case, 3 m)

2007-11-26 08:43:44 · answer #1 · answered by jgoulden 7 · 0 1

3m = 3,000mmH2O ÷ 13.6(SG of Hg) = 221mmHg + 760
= 981mmHg Absolute pressure.

(981/760) x 14.7 = 19psia)

2007-11-26 09:45:07 · answer #2 · answered by Norrie 7 · 0 0

4.265psig

Absolute pressure will be 18.965 psia <<<<<<-----answer

That's because you add 14.7psi for atmospheric pressure.

2007-11-26 09:06:44 · answer #3 · answered by Anonymous · 0 0

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