Algebra 2 FOILing Help?

Question

I understand how to foil and everything, (A+B)(C+D) = AC+AD+BC+BD...

but I just received a question that doesn't work with this method.
(t+1)(t[sqared] - t +1)
There are three coefficients in the second set and I do not know what to do.

Answer 1

(t+1)(t^2-t+1)

Like you had, (A+B)(C+D) = AC + AD + BC + BD

Add one variable

(A+B)(C+D+E) = AC + AD + AE + BC +BD +BE

so:

(t+1)(t^2-t+1) = t^3 - t^2 + t + t^2 - t +1

= t^3 + 1

Answer 2

(t+1)(t^2 - t + 1) = t^3 - t^2 + t + t^2 - t +1= t^3 + 1

^ means " to the power of" for example t^2 means t squared or t to the power of 2.

Take the first term "t" and multiply it by every term in the second expression, then take the second term "1" and multiply it by every term in the second expression also. Simplify and you get the answer. Good luck.

Answer 3

I get.... t^3 + 2*t^2 + 2*t +1.... that is two coefficients, unless u count 1 as a coefficient. So what was the question you got from someone? Let us know, You always get this with a squared unknown in an equation. please let us know what the problem is. God bless. Earl

Answer 4

(t+1)(t^2 - t + 1)=
t^3 - t^2 + t + t^2 - t +1 - collect like terms.
t^3 + 0t^2 + 0t + 1 =
t^3 + 1 - the answer

NB
From the left brackets take 't' and multiply to each term in the right brackets. Then from the left brackets take '1' and multiply it to each term in the right brackets. Finally, collect like terms.

Answer 5

(t+1)(t^2 - t +1)
t(t^2 - t + 1) + 1(t^2 - t + 1)
2t^2 - 2t + t + t^2 - t + 1

=

3t^2 - 3t + t + 1

so times the first term of the binomial by the trinomail, then the second term of the binomial times the trinomial

Answer 6

i distributed and I got t^3+1:

t(t^2-t+1) + 1(t^2-t+1)=

t^3-t^2+1t+t^2-1t+1= (turn all subtraction into addition in algebra leaving you with

t^3+(-t^2)+1t+t^2+(-1t)+1= canceling all that need to be canceled leaving you with
t^3+1

At least that's what i got, i may be completely wrong though. As i see it you can't just foil this, you can really just apply the distributive property and simplify

Answer 7

multiply everything in the first group by everything in the second group... t x t(squared)+t x -t+t x 1... etc. add all the like terms and their you are! You should get a binomial when you're done. I'm pretty sure that's right!

Answer 8

think of it this way... each term from the first parenthesis has to be multiplied with each term in the second p[arenthesis.. t * t^2, t* -t, t*1, 1*t^2, u know what i mean. its hard to type. anywho. then u get all your terms and add them together. dont forget about the negative sign. good luck.

Answer 9

i got t(to the fifth) minus - t(to the third) + 2

u just do the same thing like a regular foil

(A+B)(C+D+E)= AC+AD+AE+BC+BD+BE

Answer 10

You would do this:

t(squared) - t + 1
X t + 1
________________
t(cubed) - t(squared) + t
+ t(squared) - t + 1
_______________________
t(cubed) + 1