algebra 1 help?

Question

12. Haley and Lindsy disagree about the answer to another problem that Mrs. Johnson assigned. Haley says that (c^2+c)/(c^2) can’t be simplified. Lindsy says that it simplifies to c.

What do you think?

A Haley is right because nothing cancels.
B Lindsy is right because c^2 cancels.
C They’re both right. Either answer is acceptable.
D They’re both wrong. The correct answer is (c+1)/(c)
E They’re both wrong. The correct answer is (2c)/(c^2)

also could you explain why?

Answer 1

D.

By Lindsay's logic, if you substitute number for the values..then say random c is 3 and c ^2 is 9 then you have (9 plus 3)/3 is c (3) and 12/3 is 4.

But as in D, (c+1)/c (factoring out a "c" on both and bottom and canceling it out leads to (9+3)/9 is (3+1)/3 or 4/3 or 11/3

Answer 2

Its D.
It becomes c(c+1)/c^2 when c is taken out from numerator. Then that c cancels out with one c in the denominator and the answer is obtained.

Answer 3

Man, it's been a while. I almost forgot how much I hate math. I think it's A. the parenthesis means that you have to figure out what's inside each one before you can divide and so you can't simplify without knowing "C".

Answer 4

D. the correct answer is (c+1)/c

when you cancel out the numerator you have to take in part the whole numerator not just a part of it.

Answer 5

D

(C^2+C) simplifies to (C)(C+1).

(C^2) can simplify to (C)(C).

Therefore, you can cross out a c from both the numerator and the denominator and (C+1)/(C) is your answer.

Answer 6

B. Lindsy is right the c squared's cancle

Answer 7

D is correct. multiply numerator and denominator by (1/c)/(1/c).

Answer 8

the answer is b lindsay is right because c^2 cancels...

if u put it in this form: cc+c/cc the cc cancels coz its cc dvded by itself whch is one..so the remaining is 1c or c..

Answer 9

ther eare some websites about it i know and might search it up?

Answer 10

a