for some reason i can get all the other problems except this one.
on average, a canada goose can fly 10 mph faster than a great blue heron. find their flying speeds if a goose can fly 120 miles in the same time it takes a heron to fly 80 miles
2007-11-26 05:23:41 · 5 answers · asked by sleepinbeauty52 2 in Science & Mathematics ➔ Mathematics
the heron flys 20mph and the goose flys 30mph
2007-11-26 05:30:09 · answer #1 · answered by Anonymous · 0⤊ 0⤋
You've already got answers there, but on the off-chance that you may at some point have to work out a similar problem sometime in your life, here's how I would approach it:
It's basically a simple relationship problem. G = H + 10 is the speed relationship and the distance relationships are Gt = 120 and Ht = 80. So t = 120/G and t = 80/H, and therefore 120/G = 80/H which is the same as 80G = 120H. Then just solve for G as so: 80(H+10) = 120H which simplifies to 80H + 800 = 120H and then 800 = 40H. There you go. Many steps, but they're all simple ones.
Now that you've gone through it the hard way, the simpler way would be to have G=H+10 and G/H = 120/80 = 3/2. So G=3H/2=H+10 which is 3H=2H+20 or H=20.
2007-11-26 13:55:41 · answer #2 · answered by John R 7 · 0⤊ 0⤋
120/4=30 80/4=20
30-20=10 the answer would be 20mph for the heron and 30 mph for the goose that assuming that it is being measured in mph
2007-11-26 13:38:06 · answer #3 · answered by teri b 2 · 0⤊ 0⤋
tRY! going to webmath.com. excellent site for anyone whoe doesn't want to do their work such as myself. well I'm like 23 now but still, when I feel lazy I go there. just type your problem and press solve and thats that! hope it works for ya!
2007-11-26 13:34:20 · answer #4 · answered by Jackie 2 · 0⤊ 0⤋
d=rt
distance = rate x time
your brilliant mind can do it!
2007-11-26 13:31:30 · answer #5 · answered by reynwater 7 · 0⤊ 0⤋