Indefinite Integral?

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Evaluate the indefinite integral of (sin^2)x x(times) cos(x) dx

Answer = ? + C

2007-11-26 05:15:18 · 2 answers · asked by bradm_127 1 in Science & Mathematics ➔ Mathematics

substitute u=sin x then you have du=cos x dx.

So you get \int u^2 du=1/3 u^3.

Finally replace the u again and obtain 1/3 sin^3 x.

2007-11-26 05:24:23 · answer #1 · answered by Bernhard K 1 · 0⤊ 0⤋

Let u = sin x du = cos x dx
So we get ∫u² du = u³/3 + C = sin³ x/3 + C.

2007-11-26 05:32:06 · answer #2 · answered by steiner1745 7 · 0⤊ 0⤋