Thanks!
2007-11-26 03:34:24 · 8 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
= 3(6 - x) - x(x - 3)
= 18 - 3x - x^2 + 3x
= - x^2 + 18
Answer: - x^2 + 18
2007-11-26 03:39:46 · answer #1 · answered by Jun Agruda 7 · 3⤊ 4⤋
by expanding out the brackets:
3(6 - x) - x(x-3) = 18 - 3x - x^2 + 3x = - x^2+18=0
=> x^2 = 18
x = +/- sqrt 18
2007-11-26 11:39:42 · answer #2 · answered by sierra helene 2 · 0⤊ 5⤋
3(6-x) - x(x-3) = 18 - 3x - x^2 + 3x = -x^2 + 18
2007-11-26 11:39:10 · answer #3 · answered by Anonymous · 1⤊ 4⤋
18 - 3x -x^2 +3x
-x^2 +18
2007-11-26 11:38:14 · answer #4 · answered by Anonymous · 4⤊ 2⤋
18-3x-x^2+3x
x^2=18
x= sqrt(18)
x=3sqrt(2)
= 3*1414
2007-11-26 11:46:47 · answer #5 · answered by surmy 2 · 0⤊ 4⤋
=18-3x-x2+3x
=18-x2
x2=18
x=sqroot 18
2007-11-26 11:53:38 · answer #6 · answered by sankar 1 · 0⤊ 5⤋
it is 18-x^2
you should multiply 3 inthe first paranthese and then -x in scond one.after that you should plus them.
2007-11-26 11:59:14 · answer #7 · answered by sam wilson 1 · 0⤊ 5⤋
18 - 3x - x² + 3x
18 - 3x²
2007-11-26 15:19:09 · answer #8 · answered by Como 7 · 1⤊ 5⤋