An aircraft flying horizontally at 360kmph releases a bomb at a stationary tank 200m away.What must be the height of the aircraft above the tank if the bomb is to hit the tank?
2007-11-25 23:34:33 · 3 answers · asked by anil p 1 in Science & Mathematics ➔ Physics
The aircraft flies with 360 Km/Hr. it means 360000 meter per hour. an hour is 3600 seconds, so it flies with 100 meter per second.During this time the bomb is faling down because of grasvity. By using High= 1/2 *g*t^2 formula, witch g=9.8 M/s
and t=2 second we have : High = 1/2 * 9.8 *4 = 19.8 meter.
In this problem the air resistance was ignored.
2007-11-26 00:11:29 · answer #1 · answered by reza 4 · 0⤊ 1⤋
20 m
I can't see how 0.2m makes any difference to the release height of a real bomb on its likelihood of hitting a real tank.
The whole question just seems wrong. What on earth is a real aeroplane doing that close to the ground that close to a tank. Unless the tank had run out of ammunition the most likely outcome is that the airplane would have been shot down and the best it could hope to do is to crash, bomb and all into the tank. Silly question
2007-11-26 10:12:59 · answer #2 · answered by frothuk 4 · 1⤊ 0⤋
The bomb is assumed to travel forward at 360 km/h (find out how many metres per second) throughout the drop. Therefore, find out how many seconds it takes to travel forward 200 m.
distance = speed * time
The time it takes to fall (assuming free fall) is calculated with the formula:
altitude = 0.5 * acceleration * (time)^2
Earth gravity (therefore, the acceleration of something in free-fall) is approximately 9.8 m/s^2 (every second, the speed increases by 9.8 m/s).
2007-11-26 07:43:41 · answer #3 · answered by Raymond 7 · 1⤊ 0⤋