It costs $13 for 4 burgers and 2 drinks, and $21.50 for 5 burgers and 6 drinks. What is the cost of one burger

Question

and one drink

Answer 1

4b + 2d = 13
5b + 6d = 21.50

Multiply the top equation by 3:
12b + 6d = 39

Now subtract the second equation:
7b = 17.50

Divide both sides by 7:
b = 2.50

So a burger costs $2.50 (and a drink costs $1.50)

Answer 2

multiply the first sentence by 3 you get 3 sets of 4burgers and 2 drinks,you get 12 burgers and 6 drinks that cost $39 subtract this amount by $21.50, you get $17.5 for 7 burgers(12burgers-5 burgers)
now, 7 burgers cost $17.5
each burger cost $2.5

Answer 3

4 burgers and 2 drinks = $13
12 burgers and 6 drinks = $39 ........1
5 burgers and 6 drinks = $21.50 ......2
subtracting 2 from 1 we get
7 burgers = $17.50
1 burger = $17.50/7 = $2.50
1 drink = {$13 -- 4($2.50)}/2 = $1.50

Answer 4

This problem can be solved using the systems of equations method.

Let x be burgers and y be drinks.

Thus, we have that 4x + 2y = $13 and 5x + 6y = $21.50

So, we begin:

4x + 2y = $13
5x + 6y = $21.50

I will multiply the top equation by 3 and the bottom equation by -1. Thus we have:

12x + 6y = $39
-5x - 6y = $-21.50
-------------------------- now we "add"
7x + 0 = $17.50

7x = $17.50

x = $2.50

So, $2.50 is the price for one burger. To figure out the price of one drink, plug in the newly found x into any of the original equations. I will use 4x + 2y = 13

4($2.50) + 2y = $13

2y = $13 - 10

y = 3/2 ==> $1.50

Hope I helped!

Answer 5

$13 for 4 burgers and 2 drinks
13 = 4b + 2d
39 = 12b + 6d ..(1)

$21.50 for 5 burgers and 6 drinks
21.5 = 5b + 6d ...(2)

(1) - (2)
39 - 21.5 = 12b - 5b
17.5 = 7b
b = 2.5

Sub b = 2.5 into (2)
21.5 = 5 (2.5) + 6d
21.5 = 12.5 + 6d
6d = 21.5 - 12.5
6d = 9
d = 1.5

the cost of one burger and one drink
b + d = 2.5 + 1.5 = 4

The cost of one burger and one drink is $4.

Answer 6

let b= burger cost each
d = drink cost each

4b + 2d =13 ---eqn1
5b + 6d = 21.50 --eqn2

eqn1, b = (13 -2d)/4
substitute to eqn2

5(13-2d)/4 + 6d = 21.50

6d -10d/4 = 21.5 - 13(5)/4

d = 5.25/3.5 = 1.5 dollar ----for the drinks each
b =(13-2(1.5))/4 = 2.5 dollar ----for the burger each

Answer 7

Your first step is to write this into maths language. Call the price of one burger B, and the price of one drink D. From the info you were given, you can make two equations:

4B + 2D = 13
5B + 6D = 21.5

You need to solve these simultaneously. But do that part yourself, otherwise you won't learn anything and when it comes to a test you won't know what to do.

Answer 8

x= burgers. y = drinks. Solve for x.

3 *(4x + 2y = 13.00)
-1 *(5x + 6y = 21.50)

12x + 6y = 39.00
-5x - 6y = -21.50
____________________
7x + 0y = 17.50

x = 17.50 / 7
x = $ 2.50

Substitute x into the original equation and solve for y.

y = [13.00 - 4 (2.50)] / 2
y =(13.00 - 10.00) / 2
y = 3.00 / 2
y = $1.50

The cost of one burger and one drink is: $2.50 + $1.50 = $4.00.

Answer 9

One burger = $2.50
One drink = $1.50
Total + $4.00

Answer 10

Hello ill jut give you the answer well say each drink cost $1.50 and each bruger cost is $2.50