2007-11-25 16:53:15 · 9 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
[12]
33000/500
=66 minutes=1 hr 6 minutes
2007-11-25 16:56:12 · answer #1 · answered by alpha 7 · 2⤊ 2⤋
It would take an hour and six minutes(1.6 hrs.) to reach the hight of 33,000 ft. if an airplane's speed is 500 ft./min.
here are the equations:
33,000 ft.per minute/500 ft.per minute
=66 minutes
=1.6
2007-11-25 17:12:58 · answer #2 · answered by Anonymous · 0⤊ 1⤋
It remember, airplanes no longer clime even it remember on engine skill supercharger rato or jets so if clime 500 ft minit it no advise it save clime to 33.000 ft in sixty six minutes or one million hour 6 minutes, for exampel the taek of run wood waste som time so is faulty queston wit no longer obtrusive anser, for anser do attempt
2016-11-12 20:13:19 · answer #3 · answered by ? 4 · 0⤊ 0⤋
time = height / (rate of ascent)
= 33000 ft / (500 ft / minute)
= 33000/500 minutes
= 66 minutes
= 1 hour 6 minutes.
2007-11-25 17:03:28 · answer #4 · answered by sv 7 · 0⤊ 1⤋
33000/500=66 miutes or 1 hr and 6 minutes
2007-11-25 16:56:45 · answer #5 · answered by Anonymous · 1⤊ 2⤋
t = 33000 / 500 min
t = 330 / 5 m/n
t = 65 min
2007-11-25 20:10:01 · answer #6 · answered by Como 7 · 2⤊ 1⤋
around 21 min depending on the drag east cumulius clouds and if your on the soul plane itll take " twice that" crack drag on left wing can happen near the equator and"""""' tropic of cancer"
2007-11-25 17:00:05 · answer #7 · answered by dan l 2 · 0⤊ 2⤋
1hr. and 6min. according to basic mathematics.is it a trick question?
2007-11-25 17:06:42 · answer #8 · answered by omarparra_gman 4 · 0⤊ 0⤋
t=33000ft/500(ft/min)=66min
2007-11-25 16:57:39 · answer #9 · answered by Beautiful Dreamer 2 · 0⤊ 2⤋