Batman jumps straight down into a 500 kg. boat that is going 20 m/s while trying to catch a fleeing villain. The boat then slows to 17 m/s. What is the mass of Batman?
2007-11-25 14:49:14 · 3 answers · asked by yummy_girlscout 1 in Science & Mathematics ➔ Physics
Gee ... Does he catch the villain?
I hope that momentum is conserved and our hero just magically steps onto the speeding boat with no momentum.
m1v1= (m1+m2)v2
m1- mass of the boat
m2- mass of Batman
V1- initial speed of the boat
v2- final speed of the boat and Batman
then
m2= (m1v1 - m1v2)/v2= m1(v1-v2)/v2
m2=(500)( 20 - 17)/17=88 kg
2007-11-25 15:01:41 · answer #1 · answered by Edward 7 · 1⤊ 0⤋
Momentum = mv
m1v1 = m2v2
m1v1/v2 = m1
500kg(20m/s) / 17m/s = 588.235kg
So his mass is 88.235kg
2007-11-25 22:59:43 · answer #2 · answered by Anonymous · 0⤊ 0⤋
ur hot
2007-11-25 22:52:40 · answer #3 · answered by Anonymous · 1⤊ 1⤋