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A constant force F=6i+9j+0k moves along a straight line from (-2,-8,-6) to (-10,-2,-3). How much work is done?

2007-11-25 13:50:47 · 1 answers · asked by tchoxi2000 1 in Science & Mathematics ➔ Physics

1 answers

W= F(dot)s (scalar product)

s= P2-P1 = (-10,-2,-3) - (-2,-8,-6)
s= -12i -10j -9k
W=(6i+9j+0k) (-12i -10j -9k)
W=-72 -90 - 0= 162 (Work is an absolute value)

2007-11-26 22:35:30 · answer #1 · answered by Edward 7 · 1⤊ 0⤋

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