Solve:
x^2 - 6x + 9 = 100
2007-11-25 13:45:11 · 4 answers · asked by Aimee R 1 in Science & Mathematics ➔ Mathematics
x^2 - 6x + 9 = 100
or
x^2 - 6x -91=0
or
x^2 - 13x+7x- 91 = 0
or
x(x-13)+7(x-13)=0
or
(x+7)(x-13)=0
or x=13, -7
2007-11-25 13:49:03 · answer #1 · answered by kamal d 3 · 0⤊ 0⤋
x^2 - 6x +9 = 100
(x-3)^2 = 100
x-3 = + or - 10
x = 13 or x = -7 plug both of these into the equation and see if they equal 100. You'll see that x = -7 does not satisfy the equation. Thus x =13 is the answer.
2007-11-25 21:51:31 · answer #2 · answered by Grey Man 5 · 0⤊ 1⤋
first we have to subtract 100 from both sides
since it's an EQUATION we can do this
x^2 - 6x - 91 = 0
now what are the factors of 91
give you a hint - one is 7
(x+ the smaller)(x- the larger)
and solve
the larger is the one subtracted because the middle
number 6 is a negative
all the best
2007-11-25 21:53:11 · answer #3 · answered by tom4bucs 7 · 0⤊ 0⤋
Subtract 9 from both sides
Divide both sides by -6
Find the square root
-I think that's right..if not I'm sorry! Check it by plugging in the number as x.
2007-11-25 21:51:15 · answer #4 · answered by whing22 1 · 0⤊ 1⤋