A man weighing 750N and a woman weighing 410N have the same momentum. What is the ratio of the man's kinetic

Question

A man weighing 750N and a woman weighing 410N have the same momentum. What is the ratio of the man's kinetic energy Km to that of the woman Kw ?

Answer 1

Very similar to the other problem.

v(man) x m(man) = P; so write v(man) = P/(mman) and use

ke = 1/2 mv^2

to write out the ke for the man.

Same for the woman.

Take the ratios and P will cancel.

Answer 2

I think it's simply 75 : 41.