how would you balance this out?

Question

Octane reacts with oxygen to produce carbon dioxide and oxygen

Answer 1

I believe the other product for your reaction is water not oxygen.

First I write out the equation unbalanced:
C8H18 + O2 ---> CO2 + H2O

Next I'll change the munber of CO2's to "agree" with number of carbons in octane
C8H18 + O2 ---> 8 CO2 + H2O

Now I'll put the correct number of waters formed from the hydrogen that was in the octane:
C8H18 + O2 ---> 8 CO2 + 9 H2O

Now I'll get the correct number of oxygens in the reacant side:

C8H18 + 12 1/2 O2 ---> 8 CO2 + 9 H2O

For the balanced equation they must be all in whole numbers (no fractions) so we will double all the numbers:

2 C8H18 + 25 O2 ---> 16 CO2 + 18 H2O

Answer 2

First you have to know what octane is. It's C8H18. Also the products do not include oxygen but rather water.

C8H18 + O2 = CO2 + H2O

8 CO2s needed for 8 carbons, 9 waters for 18 hydrogens

C8H18 + O2 = 8 CO2 + 9 H2O

Now you've got 16 + 9 = 25 oxygens on the right, you need that many on the left:

C8H18 + (25/2) O2 = 8 CO2 + 9 H2O

The 25/2 is awkward so multiply everything thru by 2

2 C8H18 + 25 O2 = 16 CO2 + 18 H2O

Answer 3

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RE:
how would you balance this out?
Octane reacts with oxygen to produce carbon dioxide and oxygen

Answer 4

C8h18 O2

Answer 5

C8H18 + 12 1/2O2 -----> 8CO2 + 9H2O