2007-11-25 10:45:06 · 8 answers · asked by lori c 2 in Science & Mathematics ➔ Mathematics
Thank you everyone!
2007-11-25 10:49:44 · update #1
4(2m²+3m+1)=4(2m+1)(m+1)
2007-11-25 10:47:45 · answer #1 · answered by chasrmck 6 · 0⤊ 0⤋
8m^2 + 12m + 4
= 4(2m^2 + 3m + 1)
= 4(2m^2 + 2m + m + 1)
= 4{2m(m + 1) + 1(m + 1)}
= 4(m + 1)(2m + 1)
2007-11-25 10:49:28 · answer #2 · answered by sv 7 · 0⤊ 0⤋
OK
8m^2+12m+4
(8m +4)(m+1)
4(2m+1)(m+1)
Hope that helps!
2007-11-25 10:48:34 · answer #3 · answered by pyz01 7 · 0⤊ 0⤋
Greatest common multiple is 4
4(2m^2+3m+1)
(2m+1)(m+1)
2007-11-25 10:47:47 · answer #4 · answered by Anonymous · 0⤊ 1⤋
4(2m^2+3m+1)
4(2m+1)(m+1)
2007-11-25 10:48:57 · answer #5 · answered by Dave aka Spider Monkey 7 · 0⤊ 0⤋
4(x+1)(2x+1)
2007-11-25 10:49:59 · answer #6 · answered by Anonymous · 0⤊ 0⤋
(2m + 2)*(4m + 2)
2007-11-25 10:50:08 · answer #7 · answered by Anonymous · 0⤊ 0⤋
set u = (k+1)^2 , v = 2i , i = root(-1) u^2-v^2 = (u-v)(u+v)
2016-05-25 22:40:34 · answer #8 · answered by joana 3 · 0⤊ 0⤋