2007-11-25 10:18:42 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
3y(y-4)/-y²(y-4)= -3/y
2007-11-25 10:22:49 · answer #1 · answered by chasrmck 6 · 1⤊ 0⤋
3y^2-12y = 3y(y-4)= 3y(y-4)
4y^2-y^3 = y^2(4-y)*-1=y^2(y-4)
y-4 cancel out
3y/ -y^2= cancel out another y= -3/y
2007-11-25 18:57:14 · answer #2 · answered by Dave aka Spider Monkey 7 · 0⤊ 0⤋
To simplify, simply find the common factors on the numerator and the denominator.
Numerator:
3yË2 - 12y ==> 3y (y - 4)
Denominator:
4yË2 - yË3 ==> yË2 (4 - y)
Now, you have:
3y (y - 4)/yË2 (4 - y)
You can simplify one "y" from the numerator and denominator. You can multiply by -1 to switch the order of (4 - y) So, you'll get:
3y(y - 4)/-y2(y - 4)
-(3/y)
Hope it helped :-)
2007-11-25 18:27:51 · answer #3 · answered by Jacob F 5 · 0⤊ 1⤋
(3y^2 - 12y)/(4y^2 - y^3)
[3y(y - 4)]/[y^2(4 - y)]
Note that 4 - y = - (y - 4)
-[3y(y - 4)]/[y^2(y - 4)]
-3/y
2007-11-25 18:29:07 · answer #4 · answered by kindricko 7 · 0⤊ 0⤋
Factor out items on top and bottom:
3y(y - 4)
-------------
y^2(4 - y)
4-y = -1(y-4)
-3y
-----
y^2
y's cancel
-3
---
y
2007-11-25 18:24:05 · answer #5 · answered by Anonymous · 1⤊ 0⤋
3y(y-4)/y^2(4-y)
3y(y-4)/y^2{-(y-4)}
3y/-y^2
3/-y
-3/y
2007-11-25 18:30:13 · answer #6 · answered by Siva 5 · 0⤊ 0⤋