what is the derivative of tan^2[(x)]+ sec(x^2)?

Answer 1

y=tan^2(x)+sec(x^2)
dy/dx=2tan(x)sec^2(x)+sec(x^2)tan(x^2)(2x)
=2tan(x)sec^2(x)+2xsec(x^2)tan(x^2)

Answer 2

d[tan²(x) + sec(x²)] / dx

= 2tan(x)*sec²(x) + 2x*sec(x²)*tan(x²)