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A) 25.00mL of a 4.500 M H2SO4 solution.
B) 25.00 mLof a 0.500 M H3PO4

2007-11-25 07:25:04 · 2 answers · asked by missy 1 in Science & Mathematics Chemistry

2 answers

A) 25.00*4.500*2/1.350 = 166.7 (ml)
B) 25.00*0.500*3/1.350 = 27.8 (ml)

2007-11-27 11:53:55 · answer #1 · answered by Hahaha 7 · 0 0

it is the neutralization reaction of an acid and a base. First write the balanced equation. set up the ratio of the moles of acid to the moles of base. moles of acid/base : coefficient in balanced equation moles according to litre of acid in answer : calculated making use of information in question Ratio: moles of acid / moles of base = moles according to litre of acid in answer / moles according to litre of base in answer. to discover the moles according to litre of acid or base in a answer use the formula: moles = moles perlitre x litres making use of that ratio, discover the unknown (the moles of NaOH answer necessary ), then making use of the comparable formula above, discover the quantity of answer that is. (quantity = moles according to litre / moles)

2016-11-12 19:15:42 · answer #2 · answered by ? 4 · 0 0

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