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The weight of a cylindrical can of pea soup varies jointly with the height and the square of the radius. If a 4-inch high can with a 1-inch radius weighs 12 ounces, then what is the weight of a 5-inch high can (in ounces) with a radius of 2 inches?

2007-11-25 07:11:09 · 3 answers · asked by Monkey Kick 1 in Science & Mathematics Mathematics

3 answers

Calculate the volumes of both cans. Divide the volume of the larger can by the volume of the smaller can. Then, multiply the result by 12. That's your answer.

The fomula for finding the volume of a cyliner is pi(3.14) x (radius squared) x (height)

2007-11-25 07:14:43 · answer #1 · answered by SoulDawg 4 UGA 6 · 0 0

First of all, the volume of a can is given by πr²h where r is the radius and h is the height.

So you can compute the weight per unit volume:

12 oz ≡ π r² h = 3.14157 X 1 X4 = 12.566 cu. in.

So each 12 oz occupies 12.566 cubic inches.

A 5 inch can with a radius of 2 inches has a volume of

π X 2² X 5 = 62.83 cu. inches, and it would contain:

62.83 X 12/12.566 = 60 oz.

Hope this helps

2007-11-25 07:25:03 · answer #2 · answered by Joe L 5 · 0 0

volume of first is 4x and 12 ounces
thus 2nd with 10x has 12*2.5=30 ounces i think

hold on if area is pia r^2
double first reponse or is it 1/2 pia r^2 sorry i am rusty

2007-11-25 07:18:36 · answer #3 · answered by GOLD-FLAW 2 · 0 0

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