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A shiny new sports car sits in a parking lot of a car dealership. Above is a cargo plane, flying horizontally at 48 m/s. At the exact moment the plane is 130 m directly above the car, a heavy crate accidentally falls from its cargo doors. Relative to the car, where will the crate hit?

2007-11-25 06:43:28 · 2 answers · asked by Anonymous in Science & Mathematics Physics

2 answers

A kinematics problem in two dimensions.

Horizontal:

x - xo = vox t

x - xo = horizontal distance traveled during the drop
vox = initial horizontal velocity (48 m/s)
t = elapsed time (unknown)

Vertical:

y - yo = voy t - 1/2 g t^2

y - yo = vertical distance traveled (130 m)
voy = initial vertical velocity (zero)
g = local acceleration of gravity (-9.8 m/s^2)

Solve this equation for the elapsed time t, then use that time in the first equation to find the horizontal distance covered.

This is a standard technique: use one dimension to find time, then use that time in the other dimension to arrive at the desired answer.

2007-11-25 07:01:03 · answer #1 · answered by jgoulden 7 · 0 0

Projectile .
Vertical moion
Lets calculate time to raech the ground .
s=1/2at^2 +Ut
s=130
a=9.8
t=?
U= vertical intial velociy =0
130=1/2(9.8)(t^2)
t=5.150787536 s.

Horizontal motion

Disatnce = Speed X time
=48 X5.150787536
=247.2378017 m from the car
approx. 247m from the car .

2007-11-25 15:10:49 · answer #2 · answered by Murtaza 6 · 0 0

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