A cannonball launched with an initial velocity of 146 m/s at and angle of 30° follows a parabolic path and hits a balloon at the top of its trajectory. Neglecting air resistance, how fast is it going when it hits the balloon?
What is the acceleration of the cannonball just before it hits the balloon?
2007-11-25 06:42:17 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Physics
The horizontal velocity of the cannonball is (146 m/s)(cos 30) and does not change for the duration of the problem. Since the cannonball hits the balloon at the top of its trajectory, it has no vertical velocity at that moment, so the horizontal velocity is the answer to the first part of the problem.
The acceleration of the cannonball is 9.8 m/s^2 down; this also does not change for the duration of the problem.
2007-11-25 06:50:34 · answer #1 · answered by jgoulden 7 · 0⤊ 0⤋
is this homework?
2007-11-25 14:46:46 · answer #2 · answered by pandaface 1 · 0⤊ 0⤋