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Given: density of water = 1000 kg/m^3 and
specific heat of water = 4186 J/kg * degrees Celsius
In a showdown on the streets of Laredo,
the good guy drops a 15.8 g silver bullet, at
a temperature of 44 degrees C, into a 31 cm^3 cup
of water at 41 degrees C. Simultaneously, the bad
guy drops a 15.8 g copper bullet, at the same
initial temperature, into an identical cup of
water.
What is the coolest final temperature? (In
other words, which one ends the showdown
with the coolest cup of water in the West)?
Neglect any energy transfer into or away from
the container and assume the specific heat
of silver and copper are 234 J/kg * degrees C and
387 J/kg * degrees C (respectively). Answer in units of degrees C. Your
answer must be within 0.01% of the correct answer

2007-11-25 06:27:59 · 1 answers · asked by Handiman 3 in Science & Mathematics Physics

1 answers

Heat lost by bullet = heat gained by water

Good Guy:

(.0158 kg)(234 J/kg oC)(44 - T) = (.031 kg)(4186 J/Kg oC)(T - 41)

Solve for T.

Bad Guy:

(.0158 kg)(387 J/kg oC)(44 - T) = (.031 kg)(4186 J/Kg oC)(T - 41)

Solve for T again.

2007-11-25 06:48:09 · answer #1 · answered by jgoulden 7 · 1 0

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