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Predict the bond angles about each nitrogen in the dinitramide ion.
NNN
a. 90°
b.107.5°
c.109.5°
d.120°
e.180°
ONN
a.90°
b.107.5°
c.109.5°
d.120°
e.180°
ONO
a.90°
b.107.5°
c.109.5°
d.120°
e.180°

*Thank you! & Could you also please explain how you determined the answer?

2007-11-25 06:20:59 · 3 answers · asked by Anonymous in Science & Mathematics Chemistry

3 answers

First let's draw a diagream of dinitramide:

::O=N=O::
......|
H - N :
......|
::O=N=O::

Now looking at this, we can see that VESPR would put the central N in a tetrahedral arrangement - it has three single bonds and an electron pair. This would normally give a bond angle of 109.5 degrees, but whenever one of the groups is a lone pair, it ends up skewing the angles a bit further (like water and ammonia). So of the choices, (b) 107.5 seems best for NNN.

The side N's each have two Os and an N - a trigonal arrangement. That's 120 degrees, which would be the answer for the NNO and the ONO angles.

Hope that helps!

2007-11-26 05:39:22 · answer #1 · answered by Doctor Why 7 · 0 0

The answer to all of them is 120. I just did the web assign by guessing with two accounts, that's how I found the answer.

2007-11-27 11:35:23 · answer #2 · answered by tehPlatypi 1 · 0 0

B 107.5

2016-12-18 16:40:34 · answer #3 · answered by ? 4 · 0 0

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