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A 2.30 x 10^2-N force is pulling an 85.0-kg refrigerator across a horizontal surface. The force acts at an angle of 24.0° above the surface. The coefficient of kinetic friction is 0.200, and the refrigerator moves a distance of 5.00 m. Find: (a) the work done by the pulling force, and
(b) the work done by the kinetic frictional force.

2007-11-25 04:29:39 · 1 answers · asked by Anonymous in Science & Mathematics Physics

1 answers

a) 230*cos(24)*5
1051 J

b) I will first calculate the frictional force
(85*9.81-230*sin(24))*0.2
148 N
Work is
148*5

740 J

j

2007-11-25 07:37:13 · answer #1 · answered by odu83 7 · 1 0

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