Look at what happens to the parts.
x ==> 0 as x ==> 0 but
sin(1/x) does not converge to anything.
However, it is bounded by [-1,1]. Therefore, the broduct of those two functions will be bounded by [-x, x]. It is easy to show that this limit is zero. Pick any value of delta. As long as you choose x = epsilon, where epsilon is less than delta, you are assured that the function value is within delta of zero.
So -- the limit is zero.
2007-11-25 04:24:59
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answer #1
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answered by Ranto 7
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Sin(angle) varies from +1 to -1. This can be ignored in the limit. So the problem reduces to limit x as x tends to 0.
This is obviously 0.
2007-11-25 11:49:36
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answer #2
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answered by A.V.R. 7
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