Solve by factoring
x^2-5x-14=0
2007-11-25 02:56:36 · 7 answers · asked by meme 1 in Science & Mathematics ➔ Mathematics
or, x^2-7x+2x-14=0
or, x(x-7) +2(x-7)=0
or (x+2)(x-7)=0
or x=-2,7
2007-11-25 03:01:10 · answer #1 · answered by kamal d 3 · 1⤊ 1⤋
Find 2 numbers such that when you add them you get -5. When you multiply them, you get -14. The numbers are -7 and 2.
x^2-5x-14=x^2-7x+2x-14
=x(x-7)+2(x-7)
=(x-7)(x+2)=0
x-7=0 means x=7
x+2=0 means x=-2
2007-11-25 03:09:59 · answer #2 · answered by cidyah 7 · 0⤊ 2⤋
x^2-5x-14=0
x^2-7x+2x-14=0
x(x-7)+2(x-7)=0
(x-7)(x+2)=0
x=7,-2 ANS.
2007-11-25 03:10:36 · answer #3 · answered by Anonymous · 0⤊ 1⤋
x^2 -7x +2x-14=0.
x(x-7) +2(x-7)=0.
(x+2)(x-7)=0.
Ans. x= -2, x= 7.
2007-11-25 06:49:32 · answer #4 · answered by Sasi Kumar 4 · 0⤊ 2⤋
You should be able to get:
x = -2 or x = 7
2007-11-25 03:02:50 · answer #5 · answered by Boy, Interrupted 5 · 0⤊ 1⤋
(x - 7) (x + 2) = 0
x = 7 , x = - 2
2007-11-25 05:40:31 · answer #6 · answered by Como 7 · 3⤊ 1⤋
x^2-5x-14
x^2+-7x+2x-14
(x^2+-7x)+(2x-14)
x(x-7)+2(x-7)
(x+2)(x-7)
x= -2,7
2007-11-25 03:02:30 · answer #7 · answered by vi3t10nisgirl 4 · 1⤊ 1⤋