2007-11-25 00:40:00 · 1 answers · asked by Anonymous in Science & Mathematics ➔ Physics
mmmhhh. I don't understand what you mean by different. W is certainly not 3-separable but it seems to me that its entanglement is not genuine but is a sort of bipartite entanglement between only two of the three qubits at the time which "propagates" for "transitivity". maybe i've not been very clear
2007-11-25 01:17:43 · update #1
i think that the results for W3 in the paper it's just the mean of the 2-tangle. and that's the point: tripartite entanglement from a "mean" bipartite entanglement.
2007-11-25 01:43:35 · update #2
maybe you're right I've just misleaded it
2007-11-25 01:46:22 · update #3
Hmm...
I always thought so
|W> = [1/sqrt(3)](|001> + |010> + |100>)
since it is a sufficiently robust entanglement.
Oh well what do I know I'm just a janitor.
Does it?
Paul, besides you should know better than asking these questions before tea.
2007-11-25 01:09:12 · answer #1 · answered by Edward 7 · 0⤊ 0⤋