Water flowing through a 1.70 cm-diameter pipe can fill a
200 m bathtub in 3.50 min.
What is the speed of the water in the pipe?
2007-11-24 20:26:46 · 8 answers · asked by dawance88 2 in Science & Mathematics ➔ Physics
Sorry it's 200 L not m.
2007-11-24 20:46:55 · update #1
What is the volume V of the bathtube ?
The speed v of the water is :
v = V/(t*pi*r^2).
t = 3.50 min = 210 s; r = 1.7/2 = 0.85 cm = 8.5 *10^-3 m.
If the volume V is: V = 0.2 m^3 , the speed is: v = 4.2 m/s.
2007-11-24 20:53:02 · answer #1 · answered by Luigi 74 7 · 1⤊ 1⤋
u can calculate the flow rate of the pipe by take the volume of the tub (200m^3) and dividing it by the time it takes to fill it (3.5 min)
you'll have to convert everything to meters/sec of course so 3.5 minutes would be 210 seconds
then to find the velocity of the water coming out of the 1.7 cm diameter pipe by dividing your flow rate by the area. which is pi(r^2)
think of it like this, when you close up the end of the hose the water shoots out with more pressure, although you still fill up the tub at the same rate, the water escapes through the smaller area faster.
so,
Area = 1.7/2 = .85cm or .0085 meters .0085^2= .00007225 multiplied by pi = .0002268
flow rate = 200m^3/210sec = .95 m^3/sec
flow rate = Area x velocity
velocity = flowrate/ area .95/.0002268 = 4188.7 m/s
if, the tub is 200 m^3
i mean that is a pretty big tub right?
2007-11-24 20:51:24 · answer #2 · answered by dustin d 3 · 0⤊ 1⤋
some time is out - Mrs Smith might have travelled for 2.5s if the speed have been consistent. that is not any longer. She takes two times as lengthy to holiday that distance as she is uniformly accelerating. it may desire to help you to charm to a graph of Mrs Smith's displacement. you will see that curiously like a triangle so which you will see that the time won't be able to be 2.5s and as a substitute could desire to be two times that: 5s.
2016-10-09 10:51:23 · answer #3 · answered by Erika 4 · 0⤊ 0⤋
Maybe you mean 200 m^3 bathtub?
2007-11-24 20:37:25 · answer #4 · answered by minuteblue 6 · 0⤊ 1⤋
Ok, i think we need to know the volume of the bathtub, what does 200m means? the depth of the bathtub?
2007-11-24 20:35:25 · answer #5 · answered by Anonymous · 0⤊ 1⤋
This problem is incomplete, unless your 200 is 200 cu. meter.
If yes then
discharge = 200/3.5 = 57.143 cu m/min
discharge = Area (velocity)
57.143 = pi (0.017/2)^2 v
v = 57.143(4405.67)
v = 251753 m/min -----quite high.
2007-11-24 20:46:09 · answer #6 · answered by Anonymous · 0⤊ 1⤋
A = (π/4)d^2
Q = Av
v = (4/π)Q/d^2
v = (4/π)(200,000 cm^3/3.5 min)(1 min/60 s)/(1.70 cm)^2
v ≈ 419.59 cm/s or 4.20 m/s
2007-11-24 21:28:38 · answer #7 · answered by Helmut 7 · 0⤊ 0⤋
disregard the 1.70cm
just take the area (or volume), divided by time.
2007-11-24 20:30:29 · answer #8 · answered by Justin 3 · 0⤊ 2⤋