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pls help//

2007-11-24 19:16:44 · 4 answers · asked by Anonymous in Science & Mathematics Chemistry

4 answers

I don't agree with the first and second answers because of the term "molecule" and the third answer because of the term "equation". If we want to teach, we must use the correct wording.

The term "molecule" is used to represent the smallest unit of molecular compounds (covalent compounds) which are formed by the electron sharing of nonmetal atoms.

Since silver is a metal, this compound is an ionic compound. In water it ionizes forming Ag^+ and NO3^- ions. The smallest unit of ionic compounds which are formed by the transfer of electrons is "the formula unit".

Elements are represented by "symbols" and compounds are represented by "formulas" or "formulae". The term "equation" is used to represent a chemical change.

After correcting these misconceptions. Let's come to your question.

This is not a good question, because the amount of silver nitrate is not stated.

AgNO3 is the formula of the silver nitrate.
If it is one formula unit, it contains 1 silver, 1 nitrogen and 3 oxygen atoms.
If it is one mole, it contains 1 mole silver, 1 mole nitrogen and 3 moles oxygen atoms. Since each mole of an element contains the Avogadro's number (6.02x10^23) of atoms, in this case 1 mole AgNO3 contains 6.02x10^23 atoms of Ag, 6.02x10^23 atoms of N and 3 x 6.02x10^23 atoms of O.

2007-11-24 19:45:16 · answer #1 · answered by Guray T 6 · 0 1

Are you asking about chemical formula? Because that is AgNO3, so one Silver, one Nitrogen, and three Oxygen. That forms one molecule. How many molecules would depend on how much silver nitrate you have.

2007-11-25 03:20:03 · answer #2 · answered by niiro13 7 · 0 0

Silver nitrate is AgNO3, so one molecule contains one atom of silver, one of nitrogen, and three of oxygen.

2007-11-25 03:19:49 · answer #3 · answered by Anonymous · 0 0

It has three Oxygen atoms, one Nitrogen atom and one silver atom.

It's equation is AgNO3

2007-11-25 03:20:39 · answer #4 · answered by Mason R 2 · 0 0

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