how do I factor 81w^2-u^2?

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2007-11-24 17:39:09 · 6 answers · asked by Trisha 2 in Science & Mathematics ➔ Mathematics

81w^2-u^2
This is the difference of 2 perfect squares.
We learned a^2-b^2=(a+b)(a-b)
That rule ought to apply here as well
(9w+u)(9w-u)

2007-11-24 17:43:47 · answer #1 · answered by Grampedo 7 · 0⤊ 0⤋

81w^2 =u^2. 81= u^2/w^2. u/w=9.

2007-11-25 07:35:43 · answer #2 · answered by Sasi Kumar 4 · 0⤊ 0⤋

81w^2-u^2
=(9w)^2 - (u)^2 since a^2 - b^2=(a+b)(a-b)
=(9w+u)(9w-u)

2007-11-25 01:44:57 · answer #3 · answered by vcs7578 5 · 0⤊ 0⤋

this is a difference of squares:

(9w-u)(9+u)

2007-11-25 01:41:57 · answer #4 · answered by sayamiam 6 · 0⤊ 0⤋

(9w-u)(9+u)

2007-11-25 01:43:07 · answer #5 · answered by loone 2 · 0⤊ 0⤋

(9w-u)(9w+u)

2007-11-25 02:17:00 · answer #6 · answered by Dave aka Spider Monkey 7 · 0⤊ 0⤋