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Calculate the magnitude of the linear momentum for the following cases.
(a) a proton with mass 1.67 10-27 kg, moving with a speed of 5.65 106 m/s
=
????kg·m/s

(b) a 18.0 g bullet moving with a speed of 310 m/s
=??????????kg·m/s

(c) a 79.5 kg sprinter running with a speed of 10.5 m/s
=?????????kg·m/s

(d) the Earth (mass = 5.98 1024 kg) moving with an orbital speed equal to 2.98 104 m/s.
=????????? kg·m/s

2007-11-24 17:39:07 · 2 answers · asked by Dave 1 in Science & Mathematics Physics

2 answers

momentum = mass X velocity
a) momentum = mass X velocity
=1.67 10-27 X 5.65 106 = 9.4355X10^-21 kg·m/s

B) momentum = mass X velocity
=(18/1000)(310)=5.58 kg·m/s

C) momentum = mass X velocity
=(79.5)X(10.5) =834.75 kg·m/s

D) momentum = mass X velocity
(5.89X10^24) X (2.98X10^4)=1.78204X10^29 kg·m/s

2007-11-24 17:51:06 · answer #1 · answered by Murtaza 6 · 0 0

You have a computer, but can't use a calculator?

2007-11-25 11:51:19 · answer #2 · answered by za 7 · 0 0

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