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What happens when you apply the power rule for integration to the function 1/x?

2007-11-24 15:49:36 · 2 answers · asked by gigichic21 1 in Science & Mathematics Mathematics

2 answers

In general, the power rule for integration says:
∫(x^a) dx = [x^(a+1)]/(a+1) + C, but if you apply this to 1/x, it gives that ∫[x^(-1)] dx = [x^(0)]/0 +C, which is clearly undefined. However, we know that d/dx[ln(|x|)]=1/x, and so ∫1/x dx = ln(|x|) + C by definition.

2007-11-24 15:57:10 · answer #1 · answered by Alex I 4 · 1 0

The rule does not applied to n= -1
the answer is ln|x| + c

2007-11-24 23:57:39 · answer #2 · answered by norman 7 · 1 0

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