i need help with this problem.
y is the function of x (y=)
6x - 3(y - 1) = 4x + 8
2007-11-24 14:06:53 · 5 answers · asked by IDchecker27 2 in Science & Mathematics ➔ Mathematics
6x - 3*(y - 1) = 4x + 8
6x - 4x - 8 = 3 * (y-1)
2x - 8 = 3y - 3
3y = 2x - 8 + 3
3y = 2x - 5
y = 2x/3 - 5/3
2007-11-24 14:10:57 · answer #1 · answered by j.investi 5 · 0⤊ 0⤋
6x - 3(y - 1) = 4x + 8
6x - 3y + 3 = 4x + 8 Expand the brackets first.
-3y = 4x - 6x + 8 - 3 Move everything that is not y to one side.
-3y = - 2x + 5 Isolate y
y = (- 2x + 5)/ -3
2007-11-24 22:12:37 · answer #2 · answered by Anonymous · 0⤊ 0⤋
6x -- 3(y -- 1) = 4x + 8
=> 3y = 2x -- 5
=> y = (2/3)x -- 5/3
2007-11-24 22:11:30 · answer #3 · answered by sv 7 · 0⤊ 0⤋
6x - 3y + 3 = 4x + 8
- 3y = - 2x + 5
y = 2/3 x - 5/3
2007-11-24 22:10:42 · answer #4 · answered by norman 7 · 0⤊ 0⤋
6x-3y+3=4x+8
-3y=-2x+5
divide both sides by -3
y=2x/3 -5/3
2007-11-24 22:10:37 · answer #5 · answered by someone else 7 · 0⤊ 0⤋