If 0.100g of KClO3 reacts the volume of O2 produced at 25.0C, 0.99atm is?

Question

The reaction equation is: 2KClO3-->2KCl+3O2

Answer 1

First you need the balanced equation. This is a decomposition

2KCLO3 == 2KCl + 3O2

For every 2 moles of KClO3 you get 3 moles of O2. So calculate the moles of KClO3 and use the molar ratio to get moles of O2 produced.

Now use the ideal gas equation PV = nRT to solve for the volume. Don't forget to convert the temp. to Kelvin.