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2007-11-24 12:08:16 · 3 answers · asked by chemist 1 in Science & Mathematics Chemistry

3 answers

bromine and pentane will only really react under ultra violet (UV) light (or very intense heat). The bromine atoms will form radicals by homolytic fission:
http://en.wikipedia.org/wiki/Homolysis

These radicals will then subsitute for hydrogens, for each bromine added one molecule of HBr is formed.

This is a free radical substitution reaction.

As an aside the hydrogens on CH2 groups are more likely to be substituted than the hydrogens on CH3 groups. This has to do with the stability of the intermediate radical.

2007-11-24 13:54:45 · answer #1 · answered by Josh R 2 · 0 0

Well, when adding bromine to pentane proves that pentane has a double bond, and is unsaturated because it turns the bromine colourless.
I therefore think that this is saturation, but I'm not entirely sure. :)

2007-11-25 08:04:19 · answer #2 · answered by Perry 4 · 0 1

substitution

2007-11-24 20:27:43 · answer #3 · answered by reb1240 7 · 0 0

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